Tip Sharpness Test Aluminum Foil 0.05Mm Medical Device Testing Equipment

Tip sharpness test aluminum foil

Standard requirements:
The surface of aluminum foil should be clean and smooth without overlapping or serious fold, mildew and sand hole.
Aluminum foil is soft material with thickness of 0.05 mm ± 0.002 mm and purity of no less than 99.5%.
The tensile strength of aluminum foil shall not be less than 3 kg / mm2, and the elongation shall not be less than 3%.
Methods: suture puncture force test was used
The aluminum foil of appropriate size shall be clamped on the aluminum foil clamp, and no obvious tensile or compressive force shall be applied to the aluminum foil.
Clamp the suture needle on the needle clamp and press the control switch. Through the transmission system, the suture needle is vertically and gradually applied force on the aluminum chamber, and the swing rod rotates accordingly. When the force applied to the needle tip exceeds the strength of the aluminum foil, the needle tip will pierce the aluminum foil and contact with the electrode, and the instrument will stop applying force automatically. At this time, the value indicated by the upper pointer of the swing rod (or the value on the display instrument) is the needle piercing force of the suture needle.
Press the work control button to reset the carrying rod and pointer of the instrument.
Loosen the aluminum box clamp and move the aluminum foil in the fixture so that the distance between the piercing holes is greater than 3 letters of the suture needle diameter.
Repeat 1-4 steps, measure 3 times, and take the arithmetic mean value, which is the puncture force of suture needle.